Conversion of Concentration Units
There are instances when we are given a solution concentration in one unit and we need it in another. There are two kinds of concentration units, those that involve mass-mass ratios such as mass percentage, molality and mole fraction, and those that involve mass-volume ratios, such as molarity grams per 100 mL etc. It is relatively easy to convert one type of mass-mass concentration to another mass-mass unit of concentration. It is slightly more complex to convert concentration units from mass-mass type to concentration units that are mass-volume, since we have the additional task of converting mass to volume or vice versa. This is usually done through density. Let's look at some examples now.
Conversion of Molality to Mole Fraction
Example
What is the mole fraction of each component in a 0.500 m aqueous solution of NaCl?
From the definition of molality we know that this solution contains 0.500 mol of NaCl in 1.00 kg of water. So let's assume we have enough solution to contain 0.500 mol NaCl. This means that the solution will have 1.00 kg of water, convert this to moles.
1 mol H2O |
||||
1.00 x 103 H2O |
x |
--------------------- |
= |
55.6 mol H2O |
18.0 g H2O |
0.500 mol NaCl |
||||
XNaCl |
= |
-------------------- |
= |
0.00891 |
(0.500 + 55.6) mol solution |
|
55.6 mole H2O |
||||
Xwater |
= |
-------------------- |
= |
0.991 |
(0.500 + 55.6) mol solution |
Conversion of Molality to Mass Percent
Example
What is the mass percentage of NaCl in a 0.500 m aqueous solution of NaCl?
Again assume that you have enough solution, that it contains 0.500 mol NaCl and therefore 1.00 x 103 g of water. Convert 0.500 mol of NaCl into mass.
58.44 g NaCl |
||||
0.500 mol NaCl |
x |
---------------- |
= |
29.22 g NaCl |
1 mole NaCl |
29.22 g NaCl x 100 |
||||
mass % NaCl |
= |
----------------------------- |
= |
2.84 % |
(29.22 + 1.00 x 103) g soln |
Conversion of Mole Fraction to Molality
Example
What is the molality of NaCl in an aqueous solution in which the mole fraction of NaCl is 0.100?
Let's assume we have 1.00 mol of solution. This means that the solution will contain 0.100 mol of NaCl and 0.900 mol of water. Convert 0.900 mole of water to kilograms.
18.0 g H2O |
||||
0.900 mol H2O |
x |
---------------- |
= |
16.2 g H2O |
1 mole H2O |
0.100 mol NaCl |
||||
molality |
= |
----------------------------- |
= |
6.17 m |
0.0162 kg solvent |
Conversion of Molarity to Molality
Example
What is the molality of NaCl in an aqueous solution which 4.20 M? The density of the solution is 1.05 x 103 g/L.
Let's assume we have 1.00 L of solution. This means that the solution will contain 4.20 mol of NaCl. Convert this to mass.
58.44 g NaCl |
||||
4.20 mol NaCl |
x |
---------------- |
= |
245 g NaCl |
1 mole NaCl |
mass water = 1050 g solution - 245 g NaCl = 805 g water
4.20 mol NaCl |
||||
molality |
= |
----------------------------- |
= |
5.03 m |
0.805 kg solvent |
Conversion of Molality to Molarity
Example
What is the molarity of NaCl in an aqueous solution which 4.50 M? The density of the solution is 1.05 x 103 g/L.
Let's assume we have enough solution to contain 4.50 mol NaCl, which means that we will have 1.00 kg of water. Convert 4.20 mol of NaCl to mass.
58.44 g NaCl |
||||
4.50 mol NaCl |
x |
---------------- |
= |
263 g NaCl |
1 mole NaCl |
mass solution = 1000 g water + 263 g NaCl = 1263 g solution
Next use the density to calculate the volume of solution.
1.26 x 103 g |
||||
volume |
= |
----------------------------- |
= |
1.20 L |
1.05 x 103 g/L |
4.20 mol NaCl |
||||
molarity |
= |
----------------------------- |
= |
3.50 M |
1.20 L |