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This program provides drill in calculating the standard free energy
change and equilibrium constants from the standard cell potential. The program will show the correct solution for incorrect answers.
| Cathode Half-Reaction | Std Potential(V) | Cathode Half-Reaction | Std Potential(V) |
| Li+(aq) + e- = Li(s) | -3.04 | IO-(aq) + H2O(l) + 2 e- = I-(aq) + 2 OH-(aq) | 0.49 |
| Na+(aq) + e- = Na(s) | -2.71 | Cu+(aq) + e- = Cu(s) | 0.52 |
| Mg2+(aq) + 2 e- = Mg(s) | -2.38 | I2(s) + e- = 2 I-(aq) | 0.54 |
| Al3+(aq) + 3 e- = Al(s) | -1.66 | Fe3+(aq) + e- = Fe2+(aq) | 0.77 |
| 2 H2O(l) + 2 e- = H2(g) + 2 OH-(aq) | -0.83 | Hg22+(aq) + 2 e- = 2 Hg(l) | 0.80 |
| Zn2+(aq) + 2 e- = Zn(s) | -0.76 | Ag+(aq) + e- = Ag(s) | 0.80 |
| Cr3+(aq) + 3 e- = Cr(s) | -0.74 | Hg2+(aq) + 2 e- = Hg(l) | 0.85 |
| Fe2+(aq) + 2 e- = Fe(s) | -0.41 | ClO-(aq) + H2O(l) + 2 e- = Cl-(aq) + 2 OH-(aq) | 0.90 |
| Cd2+(aq) + 2 e- = Cd(s) | -0.40 | 2 Hg2+(aq) + 2 e- = Hg22+(aq) | 0.90 |
| Ni2+(aq) + 2 e- = Ni(s) | -0.23 | NO3-(aq) + 4 H+(aq) + 3 e- = NO(g) + 2 H2O(l) | 0.96 |
| Sn2+(aq) + 2 e- = Sn(s) | -0.14 | Br2(l) + 2 e- = 2 Br-(aq) | 1.07 |
| Pb2+(aq) + 2 e- = Pb(s) | -0.13 | O2(g) + 4 H+(aq) + 4 e- = 2 H2O(l) | 1.23 |
| Fe3+(aq) + 3 e- = Fe(s) | -0.04 | Cr2O72-(aq) + 14 H+(aq) + e- = 2 Cr3+(aq) + 7 H2O(l) | 1.33 |
| 2 H+(aq) + 2 e- = H2(g) | 0.00 | Cl2(g) + e- = 2 Cl-(aq) | 1.36 |
| Sn4+(aq) + 2 e- = Sn2+(aq) | 0.15 | MnO4-(aq) + 8 H+(aq) + 5 e- = Mn2+(aq) + 4 H2O(l) | 1.49 |
| Cu2+(aq) + e- = Cu+(aq) | 0.16 | H2O2(aq) + 2 H+(aq) + 2 e- = 2 H2O(l) | 1.78 |
| Cu2+(aq) + 2 e- = Cu(s) | 0.34 | S2O82-(aq) + 2 e- = 2 SO42-(aq) | 2.01 |
| F2(g) + 2 e- = 2 F-(aq) | 2.87 |