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Electrochemical Cells

This program provides drill in ranking oxidizing and reducing agents by strength and calculating the standard cell potential.  The program will show the correct solution for incorrect answers.

Results Total Correct Score%

Click here for Electrode Potentials

Web Author: Dr. Walter S. Hamilton

Standard Electrode Potentials in Aqueous Solutions at 25°C and 1 atm

Cathode Half-Reaction Std Potential(V) Cathode Half-Reaction Std Potential(V)

Li+(aq) + e- = Li(s)         -3.04 IO-(aq) + H2O(l) + 2 e- = I-(aq) + 2 OH-(aq) 0.49
Na+(aq) + e- = Na(s)         -2.71 Cu+(aq) + e- = Cu(s) 0.52
Mg2+(aq) + 2 e- = Mg(s)         -2.38 I2(s) + e- = 2 I-(aq) 0.54
Al3+(aq) + 3 e- = Al(s)         -1.66 Fe3+(aq) + e- = Fe2+(aq)         0.77
2 H2O(l) + 2 e- = H2(g) + 2 OH-(aq) -0.83 Hg22+(aq) + 2 e- = 2 Hg(l) 0.80
Zn2+(aq) + 2 e- = Zn(s)         -0.76 Ag+(aq) + e- = Ag(s)  0.80
Cr3+(aq) + 3 e- = Cr(s)         -0.74 Hg2+(aq) + 2 e- = Hg(l) 0.85
Fe2+(aq) + 2 e- = Fe(s)         -0.41 ClO-(aq) + H2O(l) + 2 e- = Cl-(aq) + 2 OH-(aq) 0.90
Cd2+(aq) + 2 e- = Cd(s)         -0.40 2 Hg2+(aq) + 2 e- = Hg22+(aq) 0.90
Ni2+(aq) + 2 e- = Ni(s)         -0.23 NO3-(aq) + 4 H+(aq)  + 3 e- = NO(g) + 2  H2O(l) 0.96
Sn2+(aq) + 2 e- = Sn(s)         -0.14 Br2(l) + 2 e- = 2 Br-(aq) 1.07
Pb2+(aq) + 2 e- = Pb(s)         -0.13 O2(g) +  4 H+(aq)  + 4 e- =   2  H2O(l) 1.23
Fe3+(aq) + 3 e- = Fe(s)         -0.04 Cr2O72-(aq) + 14 H+(aq) + e- = 2 Cr3+(aq) + 7 H2O(l) 1.33
2 H+(aq) + 2 e- = H2(g)         0.00 Cl2(g) + e- = 2 Cl-(aq) 1.36
Sn4+(aq) + 2 e- = Sn2+(aq)         0.15 MnO4-(aq) + 8 H+(aq)  + 5 e- = Mn2+(aq) + 4  H2O(l) 1.49
Cu2+(aq) + e- = Cu+(aq)         0.16 H2O2(aq) +  2 H+(aq)  + 2 e- =   2  H2O(l)   1.78
Cu2+(aq) + 2 e- = Cu(s)         0.34 S2O82-(aq) + 2 e- = 2 SO42-(aq) 2.01
    F2(g) + 2 e- = 2 F-(aq) 2.87
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